(2x+5)(x^2-2)=0

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Solution for (2x+5)(x^2-2)=0 equation:


Simplifying
(2x + 5)(x2 + -2) = 0

Reorder the terms:
(5 + 2x)(x2 + -2) = 0

Reorder the terms:
(5 + 2x)(-2 + x2) = 0

Multiply (5 + 2x) * (-2 + x2)
(5(-2 + x2) + 2x * (-2 + x2)) = 0
((-2 * 5 + x2 * 5) + 2x * (-2 + x2)) = 0
((-10 + 5x2) + 2x * (-2 + x2)) = 0
(-10 + 5x2 + (-2 * 2x + x2 * 2x)) = 0
(-10 + 5x2 + (-4x + 2x3)) = 0

Reorder the terms:
(-10 + -4x + 5x2 + 2x3) = 0
(-10 + -4x + 5x2 + 2x3) = 0

Solving
-10 + -4x + 5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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